Puzzle #53 Solution and Puzzle #54, “No Need to Fill Me In”

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Last week’s puzzle, “Where Does It End?”, featured state abbreviations – but not the typical two-letter postal codes. Instead all four theme entries ended in a three- or four-letter state abbreviation that can be found on either or both lists of abbreviations used by the Government Printing Office (GPO), or the Associated Press (AP). The four abbreviations combined to spell out a fifth that could also be found at the end of a grid entry:

So the answer was 7-across, FOXCONN.

Up next: Puzzle #54, “No Need to Fill Me In.”

054_noneed.puz

The answer to the metapuzzle is a six-letter plural. Submit your answer using the contact form by 11 pm Pacific Time on Monday, April 6. The puzzle gods willing, I will publish a new puzzle next Tuesday. Uncertain times …

To keep up with the puzzles: Twitter @pgwcc1; follow the blog for email reminders; rss feed if you’re set up for that.

Puzzle #52 Solution and Puzzle #53, "Where Does It End?"

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Howdy folks – I hope you’re adjusting to whatever your new reality is. Last week’s puzzle, “Character Set,” was pretty straightforward – I thought a more modest challenge might be welcome in such stressful times, and many of you agreed. There were five obvious themers and the prompt asked for a five-letter answer. Here’s the rundown:

The five long entries start with the first names of some familiar (and at least one probably-not-familiar!) fictional animal characters:

The above “character set” features SMOKEY BEAR, PETER RABBIT, WOODSY OWL, OSSIE OSTRICH, AND DEPUTY DAWG. (No, I had never heard of Ossie either.) Put together the first letters of each animal (Bear – Rabbit – Owl – Ostrich – Dawg) and you get the meta answer, BROOD, one meaning of which is a set of animals (though to be fair, usually the same kind of animal …)

Up next is Puzzle #53, “Where Does It End?”

053_wheredoesitend.puz

The answer to the metapuzzle is a grid entry that could make a fifth theme entry – one the other four combine to hint at. Submit your answer using the contact form by 11 pm Pacific Time on Monday, March 30. The puzzle gods willing, I will publish a new puzzle next Tuesday. Uncertain times …

To keep up with the puzzles: Twitter @pgwcc1; follow the blog for email reminders; rss feed if you’re set up for that.

Puzzle #52, “Character Set”

Quick post with a new puzzle – sorry for the delay.

052_characterset.puz

The answer to the metapuzzle is a five-letter word. Submit your answer using the contact form by 11 pm Pacific Time on Monday, March 23. The puzzle gods willing, I will publish a new puzzle next Tuesday. Uncertain times …

To keep up with the puzzles: Twitter @pgwcc1; follow the blog for email reminders; rss feed if you’re set up for that.

Puzzle #51 Solution

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Hey everyone –

Quick post to share last week’s solution, and I’m again copying and pasting from a solver:

Scarlet letter: A (add one letter) =
TV commercial: AD (add one letter) =
Hyperactivity: ADD (add one letter) =
Elephant Park: ADDO (add one letter) =
Building annex: ADDON (add one letter) =
ADD ONE

“Elephant Park” was the giveaway for many – because “Addo” is not a well-known thing, I had to clue this one in a way that would lead you to it (the elephant park near Port Elizabeth, SA is called Addo.)

I have a new grid constructed and partially clued, but the age of social distancing has not added to my free time – kids are at home, and my job has so far been more, not less, busy. I hope to get it out to you soon. It should be on the easy side as my puzzles go.

I hope everyone is staying safe and sane – and thankfully there are a lot of great puzzles out there if you’re stuck at home with little to do.

Puzzle #50 Solution and Puzzle #51, “Please Reiterate”

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Hi folks, I’m back. Got my big work thing done last week, and dusted off an old grid I hadn’t clued yet for this week.

Puzzle #50 was a hit – lots of solvers, and lots of you liked it. Here’s a quick solution rundown, courtesy of a solver who tends to show their work very clearly and succinctly:

Answer: FORREST GUMP (or PHILADELPHIA)
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LITTLE ODESSA – film – one of its Independent Spirit Award nominees was TIM ROTH
ENAK’S TEARS – sculpture – created by HANS ARP
BROKEBACK MOUNTAIN – film – one of its Oscars was for director ANG LEE
WHEN HARRY MET SALLY – film – its BAFTA Award was for screenwriter NORA EPHRON
THE GAMBLER – song – won a Grammy for singer KENNY ROGERS
ONCE AND AGAIN – TV show – won an Emmy for actress SELA WARD
The initial and last name of each person is found in the grid:
T. ROTH = TROTH (65D)
H. ARP = HARP (83A)
A. LEE = ALEE (26D)
N. EPHRON = NEPHRON (15A)
K. ROGERS = KROGERS (82A)
S. WARD = SWARD (24A)
The initials spell out THANKS (which is what an award winner might say), but in keeping with the puzzle theme, they also spell T. HANKS = TOM HANKS, who has won Academy Awards for FORREST GUMP and PHILADELPHIA.
Nice!

Puzzle #51 is called “Please Reiterate.”

051_pleasereiterate.puz

The answer to the metapuzzle is a six-letter phrase that does not end in S. Submit your answer using the contact form by 11 pm Pacific Time on Monday, March 16. The puzzle gods willing, I will publish a new puzzle next Tuesday.

To keep up with the puzzles: Twitter @pgwcc1; follow the blog for email reminders; rss feed if you’re set up for that.

Puzzle #49 Solution and Puzzle #50, “The Winner Is …”

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Last week’s instructions turned out to be a little too vague at first – I asked for “a large number,” which led to a surprising number of incorrect answers based on a simplistic mechanism, so I later clarified that it was “a ten-digit number.” There were still a few tricky spots, though.

The thing that just about everyone noticed was that the grid contained quite a few Os, arranged in a very peculiar way. Before the prompt change, some folks decided to count those Os, think of them as zeroes, and give the number that’s a one followed by that many zeroes. This grid had 28 Os, though a lot of people missed one, and submitted “octillion,” which is a 1 followed by 27 zeroes. (A couple people found all 28 and submitted “ten octillion.”)

If you will allow me a brief aside – I generally try to avoid looking like I’m complaining about solvers, and clearly this puzzle was tricky enough, and the instructions vague enough, that I can understand landing on the above idea … but I have to say, the fact that so many of you submitted it as an answer took me aback a little bit. A puzzle with a vague hint to count all the Os, think of them as zeroes, and then translate that into a big-number word would be pretty boring to begin with, but this execution of it, with a nonstandard grid and an extremely forced arrangement of Os – two stacks of four and three stacks of three! alternating columns! all clustered around rows 4-9! – would be, well, garbage. I’m not the world’s best puzzle constructor, but I like to think you can count on me not to feed you complete drivel.

Anyway, sorry for griping. Here’s the actual solution mechanism:

The first image above is from an online suànpán (Chinese abacus) simulator. The way the abacus works – and maybe this is less well-known than I had realized? – is that beads are slid toward the dividing bar in the middle to represent each digit; beads below the bar are worth 1, and a bead above is worth 5. So the Os were the operative beads of the abacus (inclusion of the extra beads at top and bottom would, I thought, have made for a grid far more hideous than what we got), with the fifth row of the grid acting as the bar dividing the two sections of the abacus. The number, shown at bottom, was 1,339,724,852.

Why that particular number? If you plug it into google, you’ll find that it was the official population of China according to the 2010 census (the most recent official count.)

As a totally unintended bonus, I sort of thought the grid ended up looking vaguely like a Panda.

Okay, onward. Next is puzzle #50 (!), called “The Winner Is …”

050_thewinneris.puz

The answer to the metapuzzle is either of two Academy Award-winning films.

I will once again not be able to publish a puzzle next week, so again you have plenty of time with this one. When you’re ready, submit your answer using the contact form. I hope to be back in two weeks.

To keep up with the puzzles: Twitter @pgwcc1; follow the blog for email reminders; rss feed if you’re set up for that.

Puzzle #48 Solution and Puzzle #49, “Head Count”

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After a week off – sorry about that – we’re back.

Two weeks ago I gave you a theme-packed puzzle called “Character Sequence.” There were four pairs of obvious theme entries, clued as “Roman character …” and “Greek character …” where in each case the Roman character came first.

But these were just to get you started. The actual puzzle, which asked for a company whose name was either six or two letters depending on how you looked at it, was elsewhere in the grid:

Those six doubly-highlighted entries share a feature in common: they consist of a single letter of our standard alphabet (the Roman alphabet), followed by a Greek letter, spelled out. So like the four pairs, you can think of it as a Roman “character” followed by a Greek one. The initial letters spell out IOMEGA, which similarly is a single Roman letter followed by a spelled-out Greek letter, and fits the meta prompt.

Up next is puzzle #49, “Head Count.” *** Note below that I have tweaked the meta prompt. *** Too many people are falling into a trap I thought would be too simplistic. Updated pdf and .puz file below:

049_headcount-2.puz

The answer to the metapuzzle is a large ten-digit number. Submit your answer using the contact form by Monday, February 24 at 11 p.m. Pacific Time. I’ll post the solution, and a new puzzle, next Tuesday.

To keep up with the puzzles: Twitter @pgwcc1; follow the blog for email reminders; rss feed if you’re set up for that.